4 stage floating point addition pipeline (JAVA CODE)

The 4 stages in floating point addition pipeline are:
1.Exponent comparer
2.Mantissa shifter
3.Mantissa adder
4.Normalize result
// Aim:To Implement 4 stage floating point addition pipeline import java.util.*; class fp // class of floating pt. nos. { double man; int exp; } class fp_add { static int compare_exp(fp f1,fp f2) // compares the exponent { if(f1.exp<f2.exp) { diff=f2.exp-f1.exp; // claculates difference in exponent return 1; // represents first number } else if(f2.exp<f1.exp) { diff=f1.exp-f2.exp; return 2; // represents second number } else return 0; // if both exponents are same } static fp shift_man(fp f) // shifts the mantissa by using "diff" value { for(int i=0;i<diff;++i) { f.man/=10; f.exp+=1; } return f; } static fp normalize(fp f) // normalize final result { while(f.man>=10) { f.man/=10; f.exp+=1; // exponent is -ve and hence adding 1 will increase its val ex. -5+1=-4 } return f; } static int diff; // difference in exponent values public static void main(String args[]) { Scanner scr=new Scanner(System.in); /* creating objects for two floating pt. nos. and result */ fp f1=new fp(); fp f2=new fp(); fp r=new fp(); System.out.println("Enter mantissa and exponent of x "); f1.man=scr.nextDouble(); f1.exp=scr.nextInt(); System.out.println("Enter mantissa and exponent of y "); f2.man=scr.nextDouble(); f2.exp=scr.nextInt(); int choice=compare_exp(f1,f2); System.out.print("STAGE 1(exponent comparer): The num with smaller exponent is "); if(choice==1)System.out.println("x \n");else if(choice==2)System.out.println("y \n");else System.out.println("Both are same.\n"); System.out.print("STAGE 2(mantissa shifter): "); if(choice==1) // choice is 1 hence first mantissa has to be shifted { f1=shift_man(f1); System.out.println("shifted mantissa "+f1.man+"\n"); } else if(choice==2) // choice is 2 hence second mantissa has to be shifted { f2=shift_man(f2); System.out.println("shifted mantissa "+f2.man+"\n"); } else // equal exponents System.out.println("no shifting required\n"); System.out.print("STAGE 3(mantissa adder): "); r.man=f1.man+f2.man; System.out.println("added mantissa "+r.man+"\n"); r.exp=f1.exp; // both f1 and f2 NOW have same exponents.Hence assign any one's exponent. r=normalize(r); // call the method to normalize final result. System.out.println("STAGE 4(normalize result):"); System.out.println("The normalized result is "+r.man+" * 10^"+r.exp); int c=-1*r.exp; /* Additional code to represent answer in different form ex 3.52*10^-3 will be 0.00352 (int i=0;i<c;++i) r.man=r.man/10; System.out.println("ie. The result is "+r.man);*/ } } /*OUTPUT C:\Users\Aditya\Desktop\aditya>java fp_add Enter mantissa and exponent of x 8.5 -3 Enter mantissa and exponent of y 2.345 -5 STAGE 1(exponent comparer): The num with smaller exponent is y STAGE 2(mantissa shifter): shifted mantissa 0.023450000000000002 STAGE 3(mantissa adder) added mantissa 8.52345 STAGE 4(normalize result): The normalized result is 8.52345 * 10^-3 */

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